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Published in Chess Puzzles

In continuing our highlighting of American problemist Bob Lincoln, we offer another two-mover miniature. This one is a bit trickier than Monday’s introductory puzzle. Remember: Mate in two.


Solution:

If you tried 1.Bh2 1... Rg3 stops the mate in two. The only square for the bishop is 1.Bf4 Rg7 [1...Rd8 2.Rc7#; 1...Rg6 2.Rc7#; 1...Rf8 2.Rc7#; 1...Rc8 2.bxc8=Q#; 1...Ra8+ 2.bxa8=B# or the Q.] 2.b8=N#

 


Send questions and comments to PTamburro@aol.com.

 

 

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